California Surveyors Forums

I'm a surveying student and could use some help with computing angles, azimuths, and bearings.

For example: What is the south azimuth of a line with a bearing of S 10°59'01" E?

An azimuth of 156-12-18 has a corresponding back bearing of ?

It helps if you diagram it out.

Draw N-S-E-W axis on graph paper. Then plot a bearing of S 10-59-01 E.

A South azimuth measured right from South to S 10-59-01 E would be 360 minus 10-59-01.

An azimuth of 156-12-18 looking the opposite direction is an azimuth of 336-12-18. Convert that to a bearing (hint. it is in the NW quadrant)

Thank you! I was able to understand the way you explained it.

What is the south azimuth of a line with a bearing of S 10°59'01" E? 349°00'59"

An azimuth of 156-12-18 has a corresponding back bearing of ? N 23°47'42" W

I could also use some help with computing traverses. Here's a link to what I've done so far. I'm not sure that I'm doing the latitudes and departures correctly.

https://acrobat.adobe.com/link/review?u ... 0c2d920df5

Go ahead and write out the formulas on how you are calculating each latitude and departure.

Latitude = length x cos (bearing) i.e. course B-C 484.18 x cos (42.00 decimal degree of N42°00E) = +359.82

Departure = length x sin (bearing) i.e. course B-C 484.18 x sin (42.00 decimal degree of N42°00E) = +323.98